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Trying to create a generic FK using ContentType. In admin, the menu
lists all the models. Since I only ever need to select 1 of 2 different
models, anyway to limit the choice?
Setting the choices attribute as Django complains
must be a "ContentType" instance
ContentType.objects.get() returns an instance of a particular model, not
ContentType (as one would expect), so I'm not sure how to create an
instance with the particulars I need to point to something specific in
the choices list. Here's what I have:
from django.db import models
from django.contrib.contenttypes.models import ContentType
from django.contrib.contenttypes import generic
class GenericFKExample(models.Model):
CHOICES = (
(ContentType.objects.get(model="model1"), "Model 1"),
(ContentType.objects.get(model="model2"), "Model 2"),
)
content_type = models.ForeignKey(ContentType,
choices = CHOICES,
null = True,
)
object_id = models.PositiveIntegerField(
null = True,
)
content_object = generic.GenericForeignKey(
"content_type", "object_id"
)
Obviously, if I don't use choices, it works but then I have a very long
list of model choices.
--
Adam Stein @ Xerox Corporation Email: [hidden email]
Disclaimer: Any/All views expressed
here have been proven to be my own. [ http://www.csh.rit.edu/~adam/]
--~--~---------~--~----~------------~-------~--~----~
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You're close...
change your method in CHOICES to get_for_model( _model_ )
So it should be
CHOICES = (
(ContentType.objects.get_for_model(My_Model), "Model 1"),
(ContentType.objects.get_for_model(My_Other_Model), "Model
2"),
)
Obviously, make sure you import your model before you try to use it.
On Mar 23, 3:26 pm, Adam Stein < [hidden email]> wrote:
> Trying to create a generic FK using ContentType. In admin, the menu
> lists all the models. Since I only ever need to select 1 of 2 different
> models, anyway to limit the choice?
>
> Setting the choices attribute as Django complains
>
> must be a "ContentType" instance
>
> ContentType.objects.get() returns an instance of a particular model, not
> ContentType (as one would expect), so I'm not sure how to create an
> instance with the particulars I need to point to something specific in
> the choices list. Here's what I have:
>
> from django.db import models
> from django.contrib.contenttypes.models import ContentType
> from django.contrib.contenttypes import generic
>
> class GenericFKExample(models.Model):
> CHOICES = (
> (ContentType.objects.get(model="model1"), "Model 1"),
> (ContentType.objects.get(model="model2"), "Model 2"),
> )
>
> content_type = models.ForeignKey(ContentType,
> choices = CHOICES,
> null = True,
> )
>
> object_id = models.PositiveIntegerField(
> null = True,
> )
>
> content_object = generic.GenericForeignKey(
> "content_type", "object_id"
> )
>
> Obviously, if I don't use choices, it works but then I have a very long
> list of model choices.
>
> --
> Adam Stein @ Xerox Corporation Email: [hidden email]
>
> Disclaimer: Any/All views expressed
> here have been proven to be my own. [ http://www.csh.rit.edu/~adam/]
--~--~---------~--~----~------------~-------~--~----~
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To post to this group, send email to [hidden email]
To unsubscribe from this group, send email to [hidden email]
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Thanks for the info. I also ran across 'limit_choices_to' which also
works.
On Wed, 2009-04-01 at 08:48 -0700, Lee wrote:
> You're close...
>
> change your method in CHOICES to get_for_model( _model_ )
>
> So it should be
> CHOICES = (
> (ContentType.objects.get_for_model(My_Model), "Model 1"),
> (ContentType.objects.get_for_model(My_Other_Model), "Model
> 2"),
> )
>
> Obviously, make sure you import your model before you try to use it.
>
> On Mar 23, 3:26 pm, Adam Stein < [hidden email]> wrote:
> > Trying to create a generic FK using ContentType. In admin, the menu
> > lists all the models. Since I only ever need to select 1 of 2 different
> > models, anyway to limit the choice?
> >
> > Setting the choices attribute as Django complains
> >
> > must be a "ContentType" instance
> >
> > ContentType.objects.get() returns an instance of a particular model, not
> > ContentType (as one would expect), so I'm not sure how to create an
> > instance with the particulars I need to point to something specific in
> > the choices list. Here's what I have:
> >
> > from django.db import models
> > from django.contrib.contenttypes.models import ContentType
> > from django.contrib.contenttypes import generic
> >
> > class GenericFKExample(models.Model):
> > CHOICES = (
> > (ContentType.objects.get(model="model1"), "Model 1"),
> > (ContentType.objects.get(model="model2"), "Model 2"),
> > )
> >
> > content_type = models.ForeignKey(ContentType,
> > choices = CHOICES,
> > null = True,
> > )
> >
> > object_id = models.PositiveIntegerField(
> > null = True,
> > )
> >
> > content_object = generic.GenericForeignKey(
> > "content_type", "object_id"
> > )
> >
> > Obviously, if I don't use choices, it works but then I have a very long
> > list of model choices.
> >
> > --
> > Adam Stein @ Xerox Corporation Email: [hidden email]
> >
> > Disclaimer: Any/All views expressed
> > here have been proven to be my own. [ http://www.csh.rit.edu/~adam/]
>
> --
Adam Stein @ Xerox Corporation Email: [hidden email]
Disclaimer: Any/All views expressed
here have been proven to be my own. [ http://www.csh.rit.edu/~adam/]
--~--~---------~--~----~------------~-------~--~----~
You received this message because you are subscribed to the Google Groups "Django users" group.
To post to this group, send email to [hidden email]
To unsubscribe from this group, send email to [hidden email]
For more options, visit this group at http://groups.google.com/group/django-users?hl=en-~----------~----~----~----~------~----~------~--~---
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Actually I tried to do as I suggested and I couldn't get it to
work... I ended up using the following:
from MyProject.MyApp.models import MyModel
CONTENT_TYPE_CHOICES = (ContentType.objects.get_for_model
(MyModel).id,)
class My_Other_Model(models.Model):
content_type = models.ForeignKey(ContentType, limit_choices_to=
{'id__in': CONTENT_TYPE_CHOICES})
On Apr 1, 11:48 am, Lee < [hidden email]> wrote:
> You're close...
>
> change your method in CHOICES to get_for_model( _model_ )
>
> So it should be
> CHOICES = (
> (ContentType.objects.get_for_model(My_Model), "Model 1"),
> (ContentType.objects.get_for_model(My_Other_Model), "Model
> 2"),
> )
>
> Obviously, make sure you import your model before you try to use it.
>
> On Mar 23, 3:26 pm, Adam Stein < [hidden email]> wrote:
>
> > Trying to create a generic FK using ContentType. In admin, the menu
> > lists all the models. Since I only ever need to select 1 of 2 different
> > models, anyway to limit the choice?
>
> > Setting the choices attribute as Django complains
>
> > must be a "ContentType" instance
>
> > ContentType.objects.get() returns an instance of a particular model, not
> > ContentType (as one would expect), so I'm not sure how to create an
> > instance with the particulars I need to point to something specific in
> > the choices list. Here's what I have:
>
> > from django.db import models
> > from django.contrib.contenttypes.models import ContentType
> > from django.contrib.contenttypes import generic
>
> > class GenericFKExample(models.Model):
> > CHOICES = (
> > (ContentType.objects.get(model="model1"), "Model 1"),
> > (ContentType.objects.get(model="model2"), "Model 2"),
> > )
>
> > content_type = models.ForeignKey(ContentType,
> > choices = CHOICES,
> > null = True,
> > )
>
> > object_id = models.PositiveIntegerField(
> > null = True,
> > )
>
> > content_object = generic.GenericForeignKey(
> > "content_type", "object_id"
> > )
>
> > Obviously, if I don't use choices, it works but then I have a very long
> > list of model choices.
>
> > --
> > Adam Stein @ Xerox Corporation Email: [hidden email]
>
> > Disclaimer: Any/All views expressed
> > here have been proven to be my own. [ http://www.csh.rit.edu/~adam/]
--~--~---------~--~----~------------~-------~--~----~
You received this message because you are subscribed to the Google Groups "Django users" group.
To post to this group, send email to [hidden email]
To unsubscribe from this group, send email to [hidden email]
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I wound up doing it that way as well except I used the model name rather
than the ID:
data_type = models.ForeignKey(ContentType,
limit_choices_to = {"model__in": ("model1", "model2")},
)
On Wed, 2009-04-01 at 10:34 -0700, Lee wrote:
> Actually I tried to do as I suggested and I couldn't get it to
> work... I ended up using the following:
>
> from MyProject.MyApp.models import MyModel
>
> CONTENT_TYPE_CHOICES = (ContentType.objects.get_for_model
> (MyModel).id,)
>
> class My_Other_Model(models.Model):
> content_type = models.ForeignKey(ContentType, limit_choices_to=
> {'id__in': CONTENT_TYPE_CHOICES})
>
>
> On Apr 1, 11:48 am, Lee < [hidden email]> wrote:
> > You're close...
> >
> > change your method in CHOICES to get_for_model( _model_ )
> >
> > So it should be
> > CHOICES = (
> > (ContentType.objects.get_for_model(My_Model), "Model 1"),
> > (ContentType.objects.get_for_model(My_Other_Model), "Model
> > 2"),
> > )
> >
> > Obviously, make sure you import your model before you try to use it.
> >
> > On Mar 23, 3:26 pm, Adam Stein < [hidden email]> wrote:
> >
> > > Trying to create a generic FK using ContentType. In admin, the menu
> > > lists all the models. Since I only ever need to select 1 of 2 different
> > > models, anyway to limit the choice?
> >
> > > Setting the choices attribute as Django complains
> >
> > > must be a "ContentType" instance
> >
> > > ContentType.objects.get() returns an instance of a particular model, not
> > > ContentType (as one would expect), so I'm not sure how to create an
> > > instance with the particulars I need to point to something specific in
> > > the choices list. Here's what I have:
> >
> > > from django.db import models
> > > from django.contrib.contenttypes.models import ContentType
> > > from django.contrib.contenttypes import generic
> >
> > > class GenericFKExample(models.Model):
> > > CHOICES = (
> > > (ContentType.objects.get(model="model1"), "Model 1"),
> > > (ContentType.objects.get(model="model2"), "Model 2"),
> > > )
> >
> > > content_type = models.ForeignKey(ContentType,
> > > choices = CHOICES,
> > > null = True,
> > > )
> >
> > > object_id = models.PositiveIntegerField(
> > > null = True,
> > > )
> >
> > > content_object = generic.GenericForeignKey(
> > > "content_type", "object_id"
> > > )
> >
> > > Obviously, if I don't use choices, it works but then I have a very long
> > > list of model choices.
> >
> > > --
> > > Adam Stein @ Xerox Corporation Email: [hidden email]
> >
> > > Disclaimer: Any/All views expressed
> > > here have been proven to be my own. [ http://www.csh.rit.edu/~adam/]
> --
Adam Stein @ Xerox Corporation Email: [hidden email]
Disclaimer: Any/All views expressed
here have been proven to be my own. [ http://www.csh.rit.edu/~adam/]
--~--~---------~--~----~------------~-------~--~----~
You received this message because you are subscribed to the Google Groups "Django users" group.
To post to this group, send email to [hidden email]
To unsubscribe from this group, send email to [hidden email]
For more options, visit this group at http://groups.google.com/group/django-users?hl=en-~----------~----~----~----~------~----~------~--~---
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