sum up numbers in a list

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sum up numbers in a list

 hi all,i have a list, for example;>>> L=[]>>> L.append('10')>>> L.append('15')>>> L.append('20')>>> len(L) 3>>> print L['10', '15', '20']is there a way to sum up all the numbers in a list?  the number of objects in the list is vary, around 50 to 60. all objects are 1 to 3 digit positive numbers. all i can think of is check the length of the list (in the above example, 3), then L[0]+L[1]+L[2] ......is there a better way to do the job? thanks. -- http://mail.python.org/mailman/listinfo/python-list
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Re: sum up numbers in a list

 sharon kim wrote: > i have a list, for example; > >  >>> L=[] >  >>> L.append('10') >  >>> L.append('15') >  >>> L.append('20') >  >>> len(L) > 3 >  >>> print L > ['10', '15', '20'] > > is there a way to sum up all the numbers in a list?  the number of > objects in the list is vary, around 50 to 60. all objects are 1 to 3 > digit positive numbers. the for-in statement is your friend:      S = 0      for item in L:          S += int(item) it can also be used in-line (this is called a "generator expression"):      S = sum(int(v) for v in L) or even hidden inside a built-in helper function:      S = sum(map(int, L)) -- http://mail.python.org/mailman/listinfo/python-list
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Re: sum up numbers in a list

 In reply to this post by sharon k  >>> L=['10','15','20']  >>> sum(int(x) for x in L) 45 or  >>> sum(map(int,L)) 45 sharon kim wrote: > hi all, > > i have a list, for example; > >  >>> L=[] >  >>> L.append('10') >  >>> L.append('15') >  >>> L.append('20') >  >>> len(L) > 3 >  >>> print L > ['10', '15', '20'] > > is there a way to sum up all the numbers in a list?  the number of > objects in the list is vary, around 50 to 60. all objects are 1 to 3 > digit positive numbers. > > all i can think of is check the length of the list (in the above > example, 3), then L[0]+L[1]+L[2] ...... > > is there a better way to do the job? thanks. -- http://mail.python.org/mailman/listinfo/python-list
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Re: sum up numbers in a list

 brilliant, thank you both of you, i will try that out later.:)On Wed, Aug 27, 2008 at 1:34 AM, c james wrote: >>> L=['10','15','20'] >>> sum(int(x) for x in L) 45 or >>> sum(map(int,L)) 45 sharon kim wrote: hi all, i have a list, for example;  >>> L=[]  >>> L.append('10')  >>> L.append('15')  >>> L.append('20')  >>> len(L) 3  >>> print L ['10', '15', '20'] is there a way to sum up all the numbers in a list?  the number of objects in the list is vary, around 50 to 60. all objects are 1 to 3 digit positive numbers. all i can think of is check the length of the list (in the above example, 3), then L[0]+L[1]+L[2] ...... is there a better way to do the job? thanks. -- http://mail.python.org/mailman/listinfo/python-list
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Re: sum up numbers in a list

 In reply to this post by sharon k sharon kim wrote: > is there a way to sum up all the numbers in a list?  >>> help(sum) sum(...)      sum(iterable[, start]) -> value      Returns the sum of an iterable of numbers (NOT strings) plus the value      of parameter 'start' (which defaults to 0).  When the iterable is      empty, returns start.  >>> L=[28,39,20,78490,37373,22,2,33,4,5]  >>> sum(L) 116016 -- http://mail.python.org/mailman/listinfo/python-list